... follows: On a short extension of AB, drive a stake at C, and another at any convenient point P. Lay off PD = CP and PE = BP. The extensions of AP and DE intersect at F. Now prove that EF is the same length as AB. CUMULATIVE TEST 1 1.

Title | : | The Scribner Plane Geometry |

Author | : | Arthur F. Leary, Carl Nathaniel Shuster |

Publisher | : | New York : Scribner - 1955 |

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