... Z meets l| at the point (10.13) Q] = (x1, x1) E l1, wherex1= %, and meets l2 at the point (10.14) Q2 = ()C2, a%X2) G lg, WI16Ia#39;an)C2 = 2m+ 1. ... Given that origami also solves cubic and quartic equations, the following result proved in [15 , Ch. 10] is not surprising. ... be a curve in the plane defined by an equation of the form (10.16) F(x, y)=ax2+bxy+cy2+dx+ey+f=0 where a, b, c, d, e, f G R and (a, b, c) 75 (0, 0, 0).
|Author||:||David A. Cox|
|Publisher||:||John Wiley & Sons - 2012-03-27|