So the root in the interval [1, 2] is 1.435476 to six decimal places. 11. From the graph it appears that there is a root near 2, so we take x\ = 2. Write the equation as /(x) = 2 sin x - x = 0. Then /a#39;(x) = 2 cos x - 1, 2 sin xa a xa 2sin.t SO Xn+l = xn xi = 2anbsp;...
|Title||:||Complete Solutions Manual for Stewart's Calculus, Third Edition|
|Author||:||James Stewart, Daniel Anderson, Daniel Drucker|